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Let ‘a’ be total number of balls in a bag. Balls are of three different colors i.e. black, white and red. Calculate ‘a’.

**Statement **I - Probability of getting a black ball is ⅙, a red ball is ⅙ & a white ball is ⅔.

**Statement II** – If one white ball is lost, probability of not getting a white ball is 8/23 and initial number of white balls in bag is less than 27.

Quantitative Aptitude

Answer

**Solution:****From I -**

Probability of getting a black ball is = ⅙

Let there are ‘x’ black balls & ‘6x’ total balls

Similarly, red balls= ‘x’

Probability of getting a while ball = ⅔ = 4/6

There will be 4x white balls.

a = 6x

But it can’t be solved further.**From II -**

Let here 15 m white balls and 23 m total remaining balls after 1 white ball is lost

And 23m + 1 = a

15m + 1 is initial number of white balls

15 m is multiple of 15, it could be

15, 30, 45….

But it is given that initial number is less than 27. Therefore, initial number of white balls is 15m + 1 = 16 balls, and now 15 balls are remaining. Hence 23 m = a – 1

Put m=1

a=24 balls**Hence it can be answered from (ii) alone.**