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Answer

Correct Option is 28

Solution:
x + y + z = 15
Given → x > 1, y > 2, z > 3
Least value of x = 2 highest value of x = 8
For y = 3 for y = 9
For z = 4 z = 10
When x = 2
(y, z) ⇒ (3, 10) (4, 9) (5, 8) (6, 7) (7, 6) (8, 5) (9, 4)] Total 7 sets
x = 3
(y, z) = (3, 9) (4, 8) (5, 7) (6, 6) (7, 5) (8, 4)] Total 6 sets
For x = 4 set = 5
x = 5 set = 4
x = 6 set = 3
x = 7 set = 2
x = 8 set = 1
Total integral solution = 28
 

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