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Answer

Correct Option is 30 days

Solution:
Let pipe A alone can fill the tank in ‘a’ hour
Similarly
Pipe B alone can fill the tank in ‘b’ hour
Pipe C alone can fill the tank in ‘c’ hour
Pipe D alone can fill the tank in ‘d’ hour
Pipe E alone can fill the tank in ‘e’ hour
Pipe F alone can fill the tank in ‘f’ hour
Given, Efficiency of pipe F is 66 ⅔% more than efficiency of pipe B and pipe E is 40% more than efficiency of pipe A
So, ratio of efficiency of pipe F and pipe B = 100 : 60 = 5 : 3
Therefore, ratio of time taken of pipe B and F = 5:3
And, ratio of efficiency of pipe E and A = 140 : 100 = 7 : 4
Therefore, ratio of time taken of pipe A and E = 7:4
Let, b = 5n hours
f = 3n hours
And, a = 7y hours
e = 5y hours
Given, Pipe F and pipe D alone can fill the tank in 24 hours and 60 hours respectively
So, 3n = 24 hours
n = 8 hours
So, b = 5 ×8=40 hours
Also give, A & E together can fill 4/5 th of the tank in fourteen hours
 

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