To the right of the address bar, tap More icon to Bookmark this Page.
Touch and hold the Favorites button at the bottom and Select Add Bookmark from the menu.
Share with your friends and help them crack UPSC!
Or Share on
In 2021, Tashu sold 30% Mouse at 600 rupees and 25% of rest of the Mouse at a (2×cost price of all mouse-200) and rest at (〖20〗^2+200). find the total selling price. (total no. of mouse sold by him is 80% more than cost price of mouse with Sonam in 2021).
Data Analysis and Interpretation
Correct Option is Rs.648000
Solution:Let cost price of all mouse with kunal and Mohan in 2020 be Rs. ’x’. And cost price of all mouse with Tashu & Sonam in 2020 and all mouse with Kunal in 2021 =Rs ’y’. Cost price all mouse with Tashu in 2021= Rs. 400 Cost price of shirt with Tashu in 2020 & cost price of shirt with Mohan in 2020 be 3z & 2z respectively. Cost price of all mouse with Mohan in 2021 = 400-150=Rs. 250 The sum of cost price of all the mouse with kunal in both years and cost price of mouse with Mohan in 2020 is 1200 So, y+400+x=1200 x+y=800…..(a) And y-x=x-250 2x-y=250 ….(b) From (a) & (b) x = Rs. 350 and y = Rs.450 Cost price of shirt with Sonam in 2020 = 3/5×600=Rs.360 Cost price of shirt with kunal in 2020 = 40/100×450=Rs. 180 In 2020 sum of the cost price of all the shirt with four sellers was Rs. 200 more than cost price of Iron with Mohan in 2020 So, 3z+180+2z+360=2600 5x=2050 x=412 Cost price of shirt with Tashu in 2020 = 3×412=Rs.1236 Cost price of shirt with Mohan in 2020 = 2×412=Rs.824
Get access to all of our verified questions
An Offering from
uFaber Edutech Pvt. Ltd.
No. 1 Private training for UPSC Prepartions
Office No 311, Kohinoor Commercial 1 Opposite Don Bosco High School Kurla West, Mumbai, Maharashtra 400070