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Data Analysis and Interpretation
Solution:Let quantity of vessel P be 100x litersQuantity of vessel Q be 100y liters(70y + 60y + 60y ) - (40x + 50x + 75x) = 240190y – 165x = 24038y-33x=48…. (i)And(30y + 40y + 40y) – (60x + 50x + 25x) = 60110y – 135x = 6022y – 27x = 12….(ii)From (i) & (ii)x =2, y = 3.So, quantity of vessel P = 100×2=200 litersQuantity of vessel Q = 100×3=300 litersQuantity of vessel S = 300 litersQuantity of vessel T = 200 litersRequired difference = (270 + 240 + 225) – (160 + 50 + 150)= 735 – 360 = 375.
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