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Answer

Correct Option is 375

Solution:Let quantity of vessel P be 100x liters
Quantity of vessel Q be 100y liters
(70y + 60y + 60y ) - (40x + 50x + 75x) = 240
190y – 165x = 240
38y-33x=48…. (i)
And
(30y + 40y + 40y) – (60x + 50x + 25x) = 60
110y – 135x = 60
22y – 27x = 12….(ii)
From (i) & (ii)
x =2, y = 3.
So, quantity of vessel P = 100×2=200 liters
Quantity of vessel Q = 100×3=300 liters
Quantity of vessel S = 300 liters
Quantity of vessel T = 200 liters
Required difference = (270 + 240 + 225) – (160 + 50 + 150)
= 735 – 360 = 375.
 

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