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The ratio of the present age of A to that of B is 4 : 5 and 1 year hence, B is twice as old as C at that time. If C is 14 years younger than A, then find present ages of A, B & C (in years) respectively?
36, 45 & 22
24, 30 & 10
32, 40 & 18
28, 35 & 14
40, 50 & 26
Correct Option is 36, 45 & 22
Solution:Let present age of A and B be ‘4x years’ and ‘5x years’ respectively. So, present age of C = (4x-14) years ATQ, (5x+1)=2(4x-14+1) ⇒ 8x-5x=26+1 ⇒ x=9 So, present age of A = 4x = 36 years Present age of B = 5x = 45 years And, present age of C = 4x – 14 = 22 years
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