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Answer

**Solution:**Box G is placed above box X in the same stack. More than two boxes are placed to the south-west of box G. Box T is placed to the east of box V. Box T is placed adjacent to box X. Two boxes are placed between box V and the box contains 40 balls and both are in different stack. Same number of boxes are placed above and below box V and box D. Both V and D are in same stack. Box B is placed south-east of box D and north-east of box C. Here, we have four possible cases.

Box G and box Y are placed in different stacks. Box A contains 5/8 balls to the box having 40 balls and placed to the west of Z. Case 2 and Case 3 will eliminate here and there is one more case i.e., case 4a. The box placed just below box B in the same stack contains three more balls to box A.

Balls in box V is equal to the total number of balls in box G and T. The only box placed to the south-east of box V contains four more balls to box G. Case 4 and case 4a will eliminate here so, box X is having four more balls to box G. The box placed east of C contains 3/5 number of balls to the box which is placed west of box Z. Hence, box X contains 15 balls, box G contains 11 balls and box V contains 39 balls. The number of balls in box D is a prime number. The balls in box D are less than the balls in box B but more than the balls in box A. The number of balls in box B is a multiple of 11 but less than the number of balls in the box which is placed west of box T. Total number of balls in box C and box X is equal to the total balls in box D. Sum of balls in box C and D is 47. One of the boxes contains 23 balls. So, the final arrangement is: